![]() I’d also like to add that what I have detailed above would work for literally ANY isolated Roulette bet, provided: You asked me not to attempt to do this until Wizard posts in this thread, so I won’t. ![]() The Binomial Distribution calculator can give you the probability of losing x or more where x is one more than half of all attempts. If you lose more trials than you win, then you are down money. The Wizard answered my PM indicating that there is a way to figure this out although there may not be a handy formulaįor this one, you could either use the Beating Bonuses simulator or a binomial distribution calculator the fact that these are flat bets at Even Money makes this quite easy to do if you are specifying a particular number of trials. If a player flat bets any even chance (one unit on one even chance) - what is the probability he will be down after a certain number of spins in double zero RouletteĪfter 1,000 spins - 98% probability the player will be downĪfter 600 spins - 92% probability the player will be downĪfter 100 spins - 80% probability the player will be downīut I don't know how to do the math to figure this out correctly ![]() Please don't attempt an answer until after the Wizard has posted The question has not been considered here (to my knowledge) or anywhere else that I know about By PM I posed a question to the Wizard and he indicated if I posted it he would respond
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